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rkatl
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GMATPrep - prob4 06 Aug 2006, 09:16
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another one...



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gmatornot
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GMATPrep - prob4 06 Aug 2006, 19:05
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Posted earlier.. here is the solution

https://www.gmatclub.com/phpbb/viewtopic ... highlight=
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techieGuy
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GMATPrep - prob4 06 Aug 2006, 19:25
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4 + 6x = 1/5(4+4x)

10x = 4 + 4x
6x = 4

x = 2/3
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rkatl
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GMATPrep - prob4 06 Aug 2006, 20:24
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sorry guys.. i am still missing here

as per the description:

isn't

(4+4x) + 1/5 = 4+6x

ofcourse, the answer from this is not listed.. so I am worng. But trying understand my mistake
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v1rok
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GMATPrep - prob4 06 Aug 2006, 20:31
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"x is 1/5 taller than y" means: x=6/5y

whereas

"x is taller than y by 1/5 ft" means: x-y = 1/5

Do you see where your problem was now?
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trivikram
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GMATPrep - prob4 06 Aug 2006, 20:34
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(4+4x) + (4+4x)/5 = (4+6x)

where x is the increase in eash year

sOlve for x and you get 2/3
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haas_mba07
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GMATPrep - prob4 06 Aug 2006, 21:02
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Yep.. agree with all the other posts which said 2/3

Solve by

4+6c = 6/5(4+4c)

where c = constant growth each year.
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rkatl
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GMATPrep - prob4 07 Aug 2006, 03:42
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yip. I see the my problem. Thanks, v1rok
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jaynayak
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GMATPrep - prob4 07 Aug 2006, 04:07
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Let the tree grow x feet each year.

Hence after 1st year = 4+x
after 2nd year = 4+2x

Similarily,
after 4th year = 4+4x
After 6th year = 4+6x

4+6x = 4+4x + 1/5(4+4x)
10x= 4+4x
6x = 4
x = 2/3



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
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