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yezz
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A paint crew gets a rush order to paint 80 houses in a new 28 Aug 2006, 04:18
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A paint crew gets a rush order to paint 80 houses in a new development. They paint the first y houses at a rate of x houses per week. Realizing that they'll be late at this rate, they bring in some more painters and paint the rest of the houses at the rate of 1.25x houses per week. The total time it takes them to paint all the houses under this scenario is what fraction of the time it would have taken if they had painted all the houses at their original rate of x houses per week?

(A) 0.8(80 – y)
(B) 0.8 + 0.0025y
(C) 80/y – 1.25
(D) 80/1.25y
(E) 80 – 0.25y


Good luck folks



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A paint crew gets a rush order to paint 80 houses in a new 28 Aug 2006, 08:38
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answer is B

time taken to finish at x rate per hour is 80/x
time taken with new schedule is y/x+(80-y)/1.25x

fraction is new time/old time = [y/x+(80-y)/1.25x] / 80/x = 0.8 +0.0025y
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A paint crew gets a rush order to paint 80 houses in a new 28 Aug 2006, 15:38
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yezz
A paint crew gets a rush order to paint 80 houses in a new development. They paint the first y houses at a rate of x houses per week. Realizing that they'll be late at this rate, they bring in some more painters and paint the rest of the houses at the rate of 1.25x houses per week. The total time it takes them to paint all the houses under this scenario is what fraction of the time it would have taken if they had painted all the houses at their original rate of x houses per week?

(A) 0.8(80 – y)
(B) 0.8 + 0.0025y
(C) 80/y – 1.25
(D) 80/1.25y
(E) 80 – 0.25y


Good luck folks
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(800-y)/1.25x ) + y/x
-----------------------------------> 0.8+.0025y
80/x



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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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