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Factors (also known as divisors) are those numbers that completely divide the original number. Suppose we say that: ‘a’ is a factor of ‘b’, then what does this mean?
It means that the number ‘a’ completely divides the number ‘b’ leaving no remainder.
It can also be expressed as
\(\frac{b}{a}=K\) (where K is a positive integer)
Let us take an example to understand this.
If we ask you, what are the factors of 10? What will be your response?
Since we know factors of a number are those numbers that divide the given number without leaving any remainders, factors of 10 will be 1, 2, 5 and 10.
All these numbers i.e., 1, 2, 5 and 10 will leave no remainder when divided by 10.
\(10=1\times 10+0\)
\(10=2\times 5+0\)
\(10=5\times 2+0\)
\(10=10\times 1+0\)
Example 2:
Similarly, if we ask you, what are the factors of 24? What will be your response?
We can use the same logic and say that the factors of 24 will be 1, 2, 3, 4, 6, 8, 12 and 24.
Number of factors – Easy to find?
Now that we have understood what are ‘factors’, let’s move to another important question, “How do we calculate the number of factors for a number?”
For instance, in our earlier examples, we saw that
10 has 4 factors – 1. 2, 5 and 10
24 has 8 factors – 1, 2, 3, 4, 6, 8, 12 and 24
But what if we ask you, “How many factors does 120 have?”
One way is to write down all the factors and count them manually.
But as you must have already realised that it will be a tedious process
So, is there any alternate way to find this out?
Yes, there is one. We have discussed that in detail in our article using the example of 24. You can go through that if you wish to understand the logic behind the same.
Generalformula
To generalise the formula for the total number of factors, If a number N can be prime factorised as
\(N=(P_1)^a\times (P_2)^b\times (P_3)^c ..... \)
(where, \(P_1,P_2,P_3\) and so on are distinct prime numbers)
then
total number of factors \(=(a+1)×(b+1)×(c+1)..... \)
Let’s now answer the question we asked earlier. “How many factors does 120 have?”
Solution: 120 can be prime factorised as \(120=2^3×3^1×5^1\) Thus, total number of factors of 120 \(=(3+1)×(1+1)×(1+1)=4×2×2=16 \)
Number ofodd factors
We have discussed the rationale in this article. If you want to know more about this rule, you can go through this link. We can generalize the formula for the total number of odd factors as below, If a number N can be prime factorised as
\(N=(2)^a\times (P_1)^b\times (P_2)^c ..... \)
(where \(P_1,P_2,P_3\) and so on are distinct prime numbers apart from 2)
then
number of odd factors \(=(b+1)×(c+1).....\)
The idea is to ignore the power of prime number 2 and treat the remaining number as a new number and find out the factors of it.
Let’s take an example to understand the process.
What is the number of odd factors of 120?
Solution: 120 can be prime factorised as 120 \(=2^3×3^1×5^1\)
Now we will completely ignore the power of 2.
Thus, the number will turn to \(3^1×5^1\)
Now, the number of factors of this number \(= (1+1)×(1+1)=2×2=9\)
Number ofeven factors
Although there is a formula for this, we should not be worried about it at all.
The number of factors can be either odd or even.
By now we know how to find the total number of factors and number of odd factors. So, finding number of even factors is no rocket science.
number of even factors = Total number of factors – Number of odd factors
Let’s take an example:
What is the number of even factors of 72?
Solution: 72 can be prime factorised as 72 \(=2^3×3^2\)
Total number of factors \(=(3+1)×(2+1)=4×3=12\)
Number of odd factors \(=(2+1)=3\)
Thus, number of even factors \(= 12 – 3 = 9\)
Before we finish off this article, let’s take one last example of 2700 and find its total number of factors, number of odd factors and number of even factors.
Attachment:
factors2700.png [ 18.84 KiB | Viewed 1840 times ]
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