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16 Apr 2018, 03:24
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
75% (01:12) correct
25%
(01:16)
wrong
based on 151
sessions
History
Date
Time
Result
Not Attempted Yet
For what value of 'm' will the quadratic equation x^2 - mx + 4 = 0 have real and equal roots?
(A) 16
(B) 8
(C) 2
(D) -4
(E) -2
(A) 16
(B) 8
(C) 2
(D) -4
(E) -2
16 Apr 2018, 04:41
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itisSheldon
The equation is in the form \(ax^2+bx+c=0\)
Now we need for which values \(b^2-4ac=0\)
As per the given equation : \((-m)^2-4.1.4=0\)
or m^2=16
or m = +4,-4 -4 is in the ans List.
Just a quick test : \(x^2 - (-4)x + 4 = 0\)
or \(x^2 +4x + 4 = 0\)
or \((x+2)^2 = 0\)
Hence the correct option is : D
