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18 Mar 2007, 16:51
Kudos
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Hi, it is really a good question. I solved it but I am posting it here for others to practice.
Q: Average weight of 3 boxes is 7 Kg, median weight is 9 Kg. What is the maximum possible weight of the lightest box?
Q: Average weight of 3 boxes is 7 Kg, median weight is 9 Kg. What is the maximum possible weight of the lightest box?
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19 Mar 2007, 10:49
Kudos
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If we are just talking about integers
I say 2
we know from statement X + Y = 12
from median we know since they cannot all be the same 9+9+9 = 27 so we can conclude
Y > 9
X < 9
so to find max X we need to find lowest possible value of Y
That would be 10, therefore X would be 2
I say 2
we know from statement X + Y = 12
from median we know since they cannot all be the same 9+9+9 = 27 so we can conclude
Y > 9
X < 9
so to find max X we need to find lowest possible value of Y
That would be 10, therefore X would be 2
19 Mar 2007, 11:07
Kudos
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My answer is 3.
Since avg is 7 the total is 21
median is 9
so one value is above 9 and other below it.
The value 'below' will be max when value 'above' is min
thats possible when value above is same as median 9
so max possible weight of lightest box is 21 - 9 -9 = 3
Since avg is 7 the total is 21
median is 9
so one value is above 9 and other below it.
The value 'below' will be max when value 'above' is min
thats possible when value above is same as median 9
so max possible weight of lightest box is 21 - 9 -9 = 3
