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nfa1rhp
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Data Sufficiency If x and y are nonzero integers, is x/y an 24 Mar 2007, 16:09
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Data Sufficiency

If x and y are nonzero integers, is x/y an integer?

1) x is the product of 2 and some other integer

2) There is only one pair of positive integers whose product equals y.



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mavery
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Data Sufficiency If x and y are nonzero integers, is x/y an Updated on: 25 Mar 2007, 03:21
Originally posted by mavery on 24 Mar 2007, 16:32.
Last edited by mavery on 25 Mar 2007, 03:21, edited 1 time in total.
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I don't know if I'm right, but I'm going with E...

Statement 1 says x is even...insufficient
Statement 2 says y is prime...insufficient

Together...insufficient. Because...

x/y could be 2/2 - integer
x/y could be 4/3 - not an integer

Since we have 2 possibilities for x/y, insufficient...
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Fig
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Data Sufficiency If x and y are nonzero integers, is x/y an 25 Mar 2007, 02:54
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mavery
I don't know if I'm right, but I'm going with E...

Statement 1 says x is even...insufficient
Statement 2 says y is prime...insufficient

Together...insufficient. Because...

The only even prime # is 2...so if x=2 & y=2, x/y is an integer...

But, for any other prime number, x/y will not be an integer because an odd/even doesn't give us an integer...
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The answer is (E) yes :)

But, your last sentence is wrong to me... On the numerator we have always an even : x = 2 * k * y is perfectly possible where k is an integer :)

Also, the denominator is not always an even: it is only if one of the 2 primes is 2 :)

To figure it out concretly, we could add this exemple :
o y = 5*7
o k = 3
then, x = 2 * 3 * 5*7 is still even and x / y = 2 * k = 2 * 3, an integer :)
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mavery
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Data Sufficiency If x and y are nonzero integers, is x/y an Updated on: 25 Mar 2007, 04:00
Originally posted by mavery on 25 Mar 2007, 03:24.
Last edited by mavery on 25 Mar 2007, 04:00, edited 1 time in total.
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Fig, thanks for following me around and correcting the silly errors I am making. It helps me to realize I need to be more conscious of my thought process and it keeps me from confusing the crap out of everyone else...

Using your comments, I went back and revised my previous post. Once again, thanks. :oops:
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Fig
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Data Sufficiency If x and y are nonzero integers, is x/y an 25 Mar 2007, 03:36
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mavery
Fig, thanks for following me around and correcting the silly errors I am making. It helps me to realize I need to be more conscious of my thought process on the process and it keeps me from confusing the crap out of everyone else...

Using your comments, I went back and revised my previous post. Once again, thanks. :oops:
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I'm the first to do mistake ;) :)

I would suggest u, if it's already the case, to create and keep your "silly" mistakes in an ErrorLog. :)... Once u record them in it, u would be able to draw pattern of silly mistake and then build up a methodology to avoid them :)
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[email protected]
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Data Sufficiency If x and y are nonzero integers, is x/y an 25 Mar 2007, 08:18
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my approach would be -

Statement 1 gives the set of the even numbers. x = 2, 4, 6, 8 , 10 etc...
Insuff to tell whether x/y is an integer as we don't know values of y.

Statement 2 gives y = 1, 2 , 3, 5, 7 etc.... This is not the set of only prime numbers as 1 is also the element of the set.
Insuff to tell whether x/y is an integer as we don't know values of x.

Taken both of them together:

x/y = 10/5 => integer
x/y = 2/3 => non integer

Hence both of them taken together insuff.

Answer is 'E'
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mavery
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Data Sufficiency If x and y are nonzero integers, is x/y an 25 Mar 2007, 09:32
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Good point vshaunak...I did leave out 1...
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Tuneman
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Data Sufficiency If x and y are nonzero integers, is x/y an 25 Mar 2007, 14:50
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Yes I think this problem was trying to trick you to forget about 1



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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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