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17 Aug 2007, 17:43
Kudos
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How would you solve?
If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 200% of j ?
a) .35
b) 3.5
c) 35
d) 350
e) 3500
If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 200% of j ?
a) .35
b) 3.5
c) 35
d) 350
e) 3500
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17 Aug 2007, 18:04
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above720
it takes ages
1) 125j=25k <=> 5j=k
2) 150k=50l <=> 3k=l
3) 175l=75m <=> 7l=3m
so start substiuting one by one.
1 and 2 gives us 15j=l
2 and 3 gives us 7*15j=3m <=> 35j=m
(m/j)=35
now the problem asks x% which can be
20m=200j*x <=> m=10jx
x = m/(10j) or (m/j)*(1/10)
x =35/10=3.5
17 Aug 2007, 19:51
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ouch, no way this can be a real GMAT problem! way too slow
5/4J = 1/4K
3/4K = 2/4L
7/4L = 3/4M
OR multiply out by 4
5J = K
3K = 2L
7L = 3M
then do all the crazy math to carry it through. it takes forever!
5/4J = 1/4K
3/4K = 2/4L
7/4L = 3/4M
OR multiply out by 4
5J = K
3K = 2L
7L = 3M
then do all the crazy math to carry it through. it takes forever!
