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Given:
(5 Men)(6 hours/day) can produce (10 toys/6 days)
Simplifying...
(30 man-hours/day)(6 days/10 toys) = 180 man-hours required to produce 10 toys
or....
18 man-hours to produce 1 toy


Therefore, assuming the men work at a constant rate of (18 man-hours / 1 toy):
(18 man-hours / 1 toy)(16 toys / 1)(1 / 12 men)(1 day/8 hours) = 3 days

(If you're having trouble following along, ensure that you properly label your ratios and proceed to cancel out the labels to arrive at "days")
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Let the work done by 1 man in 1 day working for 1 hour be MDH(an acronym for man days and hour)

Thus, work done by 5 men in 6 days working 6 hours per day = 5*6*6MDH = 180MDH

Now, this work = 10 toys.

Thus, 10 toys = 180 MDH

1 toy = 18 MDH

16 toys = 288 MDH.

Now, 12 men have to prepare 16 toys working 8 hours a day.

Let the total number of days be x.

Thus, 288 MDH = x*12*8 MDH
x = 288/96 = 3.

Thus, the correct option is E.
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