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22 Mar 2004, 08:25
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22 Mar 2004, 08:38
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C
n male and n female candidates have been recommended.
n/2 male and n/2 female candidates has to be selected from this lot.
using nCr formula we get
nC(n/2) * nC(n/2)
n! / (.5n)!(n-.5n)! * n! / (.5n)!(n-.5n)!
n male and n female candidates have been recommended.
n/2 male and n/2 female candidates has to be selected from this lot.
using nCr formula we get
nC(n/2) * nC(n/2)
n! / (.5n)!(n-.5n)! * n! / (.5n)!(n-.5n)!
22 Mar 2004, 10:04
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I guess B. I think C is wrong, in addition it was the answer last week.
I don't have any logic since this problem is to complicated.
But I think C is wrong cuz you can't pair the events together.
I don't have any logic since this problem is to complicated.
But I think C is wrong cuz you can't pair the events together.
