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somethingbetter
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If <x> = (x + 2) - (x + 1) - (x - 1) - (x - 2), what 31 Aug 2007, 12:14
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If = (x + 2) - (x + 1) - (x - 1) - (x - 2), what is the value of - ?


a. –196

b. –1

c. 0

d. 6

e. 202



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If <x> = (x + 2) - (x + 1) - (x - 1) - (x - 2), what 31 Aug 2007, 13:12
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If <x> = (x + 2) - (x + 1) - (x - 1) - (x - 2), what is the value of <100> - <100>?


a. –196

b. –1

c. 0

d. 6

e. 202
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Isn`t it zero? I mean the difference between ANY two equal numbers is zero.
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If <x> = (x + 2) - (x + 1) - (x - 1) - (x - 2), what 31 Aug 2007, 13:30
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NOOOOO, my mistake it is actually <negative> - <100>
sometimes you gotta review capy 'n' paste too...huh!!

there is a minus before previous 100 (I mean the previous 100 is negative). i wonder why is not it getting printed, it might have to do something with HTML tags and these brackets, lets write it other way---

i.e.

If {x} = (x + 2) - (x + 1) - (x - 1) - (x - 2),
what is the value of {-100} - {100}

a. –196

b. –1

c. 0

d. 6

e. 202
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If <x> = (x + 2) - (x + 1) - (x - 1) - (x - 2), what 31 Aug 2007, 13:49
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NOOOOO, my mistake it is actually <negative> - <100>
sometimes you gotta review capy 'n' paste too...huh!!

there is a minus before previous 100 (I mean the previous 100 is negative). i wonder why is not it getting printed, it might have to do something with HTML tags and these brackets, lets write it other way---


i.e.

If {x} = (x + 2) - (x + 1) - (x - 1) - (x - 2),
what is the value of {-100} - {100}

a. –196

b. –1

c. 0

d. 6

e. 202
Show more


then,

I agree with u,

I keep getting +400
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If <x> = (x + 2) - (x + 1) - (x - 1) - (x - 2), what 31 Aug 2007, 14:36
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Thats exactly I got. OA says---

The correct answer is E. Apply the defined operation to -100 and to 100 in turn, by substituting each value for x in the operation:

<100>; = -98 - 99 - (-101) - (-102) = -98 - 99 + 101 + 102 = 6

<100>; = 102 - 101 - 99 - 98 = -196

Then combine the two results:

<100>; - <100>; = 6 - (-196) = 6 + 196 = 202
------------------

I guess it's wrong and it must be +99 instead of -99. Please let me know if you do not agree.
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If <x> = (x + 2) - (x + 1) - (x - 1) - (x - 2), what 31 Aug 2007, 14:40
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NOOOOO, my mistake it is actually <negative> - <100>
sometimes you gotta review capy 'n' paste too...huh!!

there is a minus before previous 100 (I mean the previous 100 is negative). i wonder why is not it getting printed, it might have to do something with HTML tags and these brackets, lets write it other way---


i.e.

If {x} = (x + 2) - (x + 1) - (x - 1) - (x - 2),
what is the value of {-100} - {100}

a. –196

b. –1

c. 0

d. 6

e. 202
Show more


I get 0.

{x} = (x + 2) - (x + 1) - (x - 1) - (x - 2) = x+2-x-1-x+1-x+2
= 4 - 2x

{-100} - {100} = (4+200) - (4-200) = 4+200-4+200 = 400
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If <x> = (x + 2) - (x + 1) - (x - 1) - (x - 2), what 31 Aug 2007, 15:07
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bkk145
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NOOOOO, my mistake it is actually <negative> - <100>
sometimes you gotta review capy 'n' paste too...huh!!

there is a minus before previous 100 (I mean the previous 100 is negative). i wonder why is not it getting printed, it might have to do something with HTML tags and these brackets, lets write it other way---


i.e.

If {x} = (x + 2) - (x + 1) - (x - 1) - (x - 2),
what is the value of {-100} - {100}

a. –196

b. –1

c. 0

d. 6

e. 202

I get 0.

{x} = (x + 2) - (x + 1) - (x - 1) - (x - 2) = x+2-x-1-x+1-x+2
= 4 - 2x

{-100} - {100} = (4+200) - (4-200) = 4+200-4+200 = 400
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:)
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Fig
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If <x> = (x + 2) - (x + 1) - (x - 1) - (x - 2), what 31 Aug 2007, 15:20
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I think the OA is wrong too :)....No answer matches :)

o <x> = (x + 2) - (x + 1) - (x - 1) - (x - 2)
= 4 - 2*x
o <-x> = 4 - 2*(-x) = 4 + 2*x

So,
<-x> - <x> = (4 + 2*x) - (4 - 2*x)
= 4*x

Thus,
<-100> - <100> = 4*100 = 400
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If <x> = (x + 2) - (x + 1) - (x - 1) - (x - 2), what 31 Aug 2007, 17:53
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somethingbetter
If = (x + 2) - (x + 1) - (x - 1) - (x - 2), what is the value of - ?


a. –196

b. –1

c. 0

d. 6

e. 202
Show more


im gettin 192...
x(100)= 102-101-99-98 = -96
so -=-(-96)-(-96)= 96 +96=192



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
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