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LM
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ywilfred
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beckee529
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LM
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beckee529
ywilfred
Isn't this the same question as the one mgmat posted on their challenge?

yes! eeerie-ly similar if you ask me..

https://www.gmatclub.com/forum/t52818


Hi,

I just checked the link, and yes you are right, the questions is same. Now the point shouldn't be, it's the same or it isn't, the point for all of us being here in GClub is to be able to solve the questions. Could you guys please focus and help me reaching the solution instead of similarities between them?

Regards,
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KillerSquirrel
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The trick is to understand that the question really asks us for the odds that in a group of four workes (w1 - w4) ---> w1< w2 < w3 < w4.

Since we have four workers, the total possibable arrangements is 4! = 24 but in only one possibable arrangement can w1 < w2 < w3< w4 so the probability is 1/24.

Hence for any four workers chosen the probability is 1/24 , no matter how many workers we started with (just ignore the 99 number).

the answer is (D)

:)
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ywilfred
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LM
beckee529
ywilfred
Isn't this the same question as the one mgmat posted on their challenge?

yes! eeerie-ly similar if you ask me..

https://www.gmatclub.com/forum/t52818

Hi,

I just checked the link, and yes you are right, the questions is same. Now the point shouldn't be, it's the same or it isn't, the point for all of us being here in GClub is to be able to solve the questions. Could you guys please focus and help me reaching the solution instead of similarities between them?

Regards,


okay, i thought there was a solution on that link... anyway, squirrel solved it .. :wink:
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ethan_casta
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this is a tough problem. i was trying all sorts of useless things and then i figured i'd just read the answer to save my time.

i'm glad i did.



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