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16 Sep 2014, 00:50
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What was Silvia's income in December?
(1) In December, Silvia's income was $50 more than her average (arithmetic mean) monthly income for the year.
(2) In December, Silvia's income was twice her average (arithmetic mean) monthly income for the year.
(1) In December, Silvia's income was $50 more than her average (arithmetic mean) monthly income for the year.
(2) In December, Silvia's income was twice her average (arithmetic mean) monthly income for the year.
16 Sep 2014, 00:50
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Official Solution:
What was Silvia's income in December?
(1) In December, Silvia's income was $50 more than her average (arithmetic mean) monthly income for the year.
The above gives the following equation: \(December \ income = Average \ income + $50\). Not sufficient.
(2) In December, Silvia's income was twice her average (arithmetic mean) monthly income for the year.
The above gives the following equation: \(December \ income=2*Average \ income\). Not sufficient.
(1)+(2) We have two distinct linear equations with two variables, \(December \ income = Average \ income + $50\) and \(December \ income=2*Average \ income\), hence we can solve it. Sufficient.
Answer: C
What was Silvia's income in December?
(1) In December, Silvia's income was $50 more than her average (arithmetic mean) monthly income for the year.
The above gives the following equation: \(December \ income = Average \ income + $50\). Not sufficient.
(2) In December, Silvia's income was twice her average (arithmetic mean) monthly income for the year.
The above gives the following equation: \(December \ income=2*Average \ income\). Not sufficient.
(1)+(2) We have two distinct linear equations with two variables, \(December \ income = Average \ income + $50\) and \(December \ income=2*Average \ income\), hence we can solve it. Sufficient.
Answer: C
21 Oct 2023, 08:25
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
