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Ravshonbek
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A luxury liner, Queen Marry II, is transporting several cats 12 Nov 2007, 07:37
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A luxury liner, Queen Marry II, is transporting several cats as well as the crew (sailors, a cook, and one-legged captain) to a nearby port. Altogether, these passengers have 15 heads and 41 legs. How many cats does the ship host?

3
5
6
7
8

any nice aproaches?



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A luxury liner, Queen Marry II, is transporting several cats 12 Nov 2007, 10:03
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sportyrizwan
C

6 cats
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can you post ur approach in coming to that answer please
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Damager
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A luxury liner, Queen Marry II, is transporting several cats 12 Nov 2007, 10:04
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Ravshonbek
A luxury liner, Queen Marry II, is transporting several cats as well as the crew (sailors, a cook, and one-legged captain) to a nearby port. Altogether, these passengers have 15 heads and 41 legs. How many cats does the ship host?

3
5
6
7
8

any nice aproaches?
Show more


Let there be c cats and s sailors
Everyone has 1 head so
C+S+1 (head of captain) +1 (head of chef)=15
C+S=15-2=13 (1)

Cats 4 legs sailor 12 legs chef 2 legs and cpatain 1 leg

4*C+2*S+2 (legs of chef) +1 (leg of captain) = 41

4*c+2*S=38

2*c+s=19 (II)
C+s=13 (from 1)

sub (1 from II

c=19-13=6

Abswer 6
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A luxury liner, Queen Marry II, is transporting several cats 12 Nov 2007, 10:06
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Legs

4C + 2S = 38

Heads

C + S = 13

Solving for C and S

C = 6 and S = 7
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Ravshonbek
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A luxury liner, Queen Marry II, is transporting several cats 12 Nov 2007, 10:08
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thanks guys, i think there is no other method aside from building system of equations
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priyankurml
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A luxury liner, Queen Marry II, is transporting several cats 12 Nov 2007, 10:18
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I pulled out Captain from pool.


Heads: Cats+(sailors+cook)+captain = 15
Heads: Cats+(sailors+cook) = 14
Legs: 4Cats +2(sailors+cook)+captain = 41
Legs: 4Cats +2(sailors+cook) = 40

Let x is the cats' number
4x+2(14-x) = 40
4x+28-2x = 40
x=6

C
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A luxury liner, Queen Marry II, is transporting several cats 12 Nov 2007, 11:17
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i just tried numbers..i think this approach seems to work faster in this sort of a problem..



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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