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yogachgolf
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In year X, 8.7 percent of the men in the labor force were 30 Dec 2007, 14:48
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In year X, 8.7 percent of the men in the labor force were unemployed in June compared with 8.4 percent is May. If the number of men in the labor force was the same for both months, how many men were unemployed in June of that year?

(1) In May of year X, the number of unemployed men in the labor force was 3.36 million.

(2) In year X, 120,000 more men in the labor force were unemployed in June than in May



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yogachgolf
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In year X, 8.7 percent of the men in the labor force were 30 Dec 2007, 15:42
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yogachgolf
In year X, 8.7 percent of the men in the labor force were unemployed in June compared with 8.4 percent is May. If the number of men in the labor force was the same for both months, how many men were unemployed in June of that year?

(1) In May of year X, the number of unemployed men in the labor force was 3.36 million.

(2) In year X, 120,000 more men in the labor force were unemployed in June than in May
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Please ignore this one...
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pmenon
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In year X, 8.7 percent of the men in the labor force were 30 Dec 2007, 16:24
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now im curious about the answer.

Is it D ?
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jimmyjamesdonkey
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In year X, 8.7 percent of the men in the labor force were 30 Dec 2007, 16:28
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It's D.

1) 3.36/8.4%(x) where x is the total # of men in the labor force.

2) u = 8.4%(x) and u + 120,000 = 8.7(x)
Solve for x, then calculate unemployed for june.
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In year X, 8.7 percent of the men in the labor force were 30 Dec 2007, 16:29
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I'd still like the oA?
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siddhans
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In year X, 8.7 percent of the men in the labor force were 30 Sep 2011, 19:28
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yogachgolf
In year X, 8.7 percent of the men in the labor force were unemployed in June compared with 8.4 percent is May. If the number of men in the labor force was the same for both months, how many men were unemployed in June of that year?

(1) In May of year X, the number of unemployed men in the labor force was 3.36 million.

(2) In year X, 120,000 more men in the labor force were unemployed in June than in May
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Is my approach right?

1) 3.36 mil ---> 8.4 %
Therefore 8.7 % = 3.36 * 8.4
-----------
8.7

Thus 1 is sufficient

2) 8.7 - 8.4 = 0.3%

0.3% -----> 120, 000

Therefore 8.7 % = 8.7 * 120,000
-------------
0.3

Thus 2 nd statement is sufficient

Thus OA = D


Let me know if my approach is correct...



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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