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10 Jun 2008, 04:42
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Detailed solution will be appreciated.
Thanks
Thanks
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10 Jun 2008, 04:56
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Let total work be W
Then work done by one machine in one day = W/(12X6)
Let n machines be required for 8 days total work done = W/(12X6) X n X 8 which should be again W
hence n = 9 so 3 more machines are required to complete the the work in 8 days.
Alternatively:
W is directly proportional to number of machines and number of days
thus 12X 6 = n X 8 implies n=9 thus 3 more are required.
Then work done by one machine in one day = W/(12X6)
Let n machines be required for 8 days total work done = W/(12X6) X n X 8 which should be again W
hence n = 9 so 3 more machines are required to complete the the work in 8 days.
Alternatively:
W is directly proportional to number of machines and number of days
thus 12X 6 = n X 8 implies n=9 thus 3 more are required.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
