Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 1001:00 AM EDT
-02:00 AM EDT
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more.
Sep 1008:00 PM PDT
-09:00 PM PDT
Free- full-length test + 15 concept videos + 150+ short videos + study plan!
Sep 0410:00 AM EDT
-11:59 PM EDT
We’ve worked incredibly hard to build TTP into the best test prep experience possible, and it would mean a lot to us to win Newsweek’s 2026 Readers’ Choice Award for Best Test Prep. If TTP has helped you, we’d be incredibly grateful for your vote.
Sep 0812:30 AM EDT
-01:30 AM EDT
Looking for your GMAT motivation to break through the score plateau? Pragati improved her score by massive 160 points with strategic guidance and hard-work! Find out how personalized mentorship and a strong mindset can turn GMAT struggles into success.
Sep 0907:00 AM PDT
-10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway- Sep 09
10:00 AM PDT
-11:00 AM PDT
Three MBA applications. Three rejections. No interview invites. A year later, Aman was admitted to Cambridge Judge, SMU, and IMD. In this episode of MBA Admit Stories, Aman shares how he rebuilt his MBA application... 
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2107:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
27 Jun 2008, 09:55
Kudos
Bookmarks
A man chooses an outfit from 3 different shirts, 2 different pairs of shoes, and 3 different pants. If he randomly selects 1 shirt, 1 pair of shoes, and 1 pair of pants each morning for 3 days, what is the probability that he wears the same pair of shoes each day, but that no other piece of clothing is repeated?
A. 1/ 3^6 x 1/2^3
B. 1/ 3^6 x 1/2
C. 1/ 3^4
D. 1/ 3^2 x 1/2
E. 5 x 1/ 3^2
A. 1/ 3^6 x 1/2^3
B. 1/ 3^6 x 1/2
C. 1/ 3^4
D. 1/ 3^2 x 1/2
E. 5 x 1/ 3^2
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
27 Jun 2008, 10:24
Kudos
Bookmarks
total number of ways the man can select his clothes on a day = 3*3*2
on 3 days = (3*3*2)^3
On day 1
number of ways shoes can be selected = 2
number of ways shirts can be selected = 3
number of ways pants can be selected = 3
on day 2
number of ways shoes can be selected = 1 (has to select the same pair of shoes)
number of ways shirts can be selected = 2 (can not repeat the shirt)
number of ways pants can be selected = 2 (can not repeat the pants)
On day 3
number of ways shoes can be selected = 1 (has to select the same pair of shoes)
number of ways shirts can be selected = 1 (has to take the third shirt)
number of ways pants can be selected = 1 (has to take the last pants)
Probability = (2*3*3)*(1*2*2)*(1*1*1) / (3*3*2)^3
= 1 / 3^4... option C
on 3 days = (3*3*2)^3
On day 1
number of ways shoes can be selected = 2
number of ways shirts can be selected = 3
number of ways pants can be selected = 3
on day 2
number of ways shoes can be selected = 1 (has to select the same pair of shoes)
number of ways shirts can be selected = 2 (can not repeat the shirt)
number of ways pants can be selected = 2 (can not repeat the pants)
On day 3
number of ways shoes can be selected = 1 (has to select the same pair of shoes)
number of ways shirts can be selected = 1 (has to take the third shirt)
number of ways pants can be selected = 1 (has to take the last pants)
Probability = (2*3*3)*(1*2*2)*(1*1*1) / (3*3*2)^3
= 1 / 3^4... option C
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
