If a and b are integers, and |a| |b|, is a |b|

Question

If a and b are integers, and |a| > |b|, is a · |b| = 0

zeenie · Answer

D for me.

|a| > |b| is possible when

a>b (3,2)
-a>-b (-3,-2)
-a>b (-3,2)

1 says a<0.
we have two possiblities.
(-3,-2) for this a-|b|=-5 and (a-b)=-1
Inequality does not hold
For (-3,2)
a-|b| = -5 and (a-b)= -5
The inequality does not hold, SUFF

Option 2 says ab>0
Two possibilities
a>0, b>0 (3,2)
OR
a<0, b<0 (-3,-2)
Inequality does not hold

Suff
Hence D

Please post the OA

walker · Answer

E a=-2, b=-1 --> true (-2<-1) a=-100, b=-0.1 --> false (-10<-99.9)

gmatnub · Answer

Sorry zeenie, the OA is E.

The OE is attached:

walker · Answer

a|b| < a-b --> a(|b|-1) < -b

from both statement: a and b are negative.
if |b|>1 ---> negative * positive < small positive --> true
if |b|<1 ---> negative * negative < small positive --> positive < positive --> we can choose a huge negative value of a in order to get larger positive number of a(|b|-1) than -b.

This is a key to construct our examples.

zeenie · Answer

oops !!! Read the question wrong !!

I read it as
a-|b| < a – b?
apology !!

FN · Answer

i get E..

pick a=1 or -1 b=10, -10

1*10=0

ok so pick b=0

-1*0>-1-0 No

and the above example..

E

If a and b are integers, and |a| > |b|, is a |b| < a

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