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22 Jul 2008, 07:39
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There are 20 red marbles, 20 blue marbles, 5 white marbles, and 5 green marbles in a bag. If two balls are to be selected at random, without replacement, what is the probability of getting two balls with the same color?
A. 4/7
B. 19/25
C. 16/49
D. 32/49
E. 32/50
A. 4/7
B. 19/25
C. 16/49
D. 32/49
E. 32/50
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Updated on: 22 Jul 2008, 07:48
Originally posted by jallenmorris on 22 Jul 2008, 07:44.
Last edited by jallenmorris on 22 Jul 2008, 07:48, edited 2 times in total.
Last edited by jallenmorris on 22 Jul 2008, 07:48, edited 2 times in total.
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16/49
i did
Chance to same color for each color = \((\frac{20}{50}*\frac{19}{49})*2 + (\frac{5}{50}*\frac{4}{49})*2\) (times 2 because there are 20 Red and 20 blue, so same numbers and same thing for White and Green with 5 each.
\(= \frac{76}{245} + \frac{4}{245} = \frac{80}{245} = \frac{16}{49}\)
Chance to select one
i did
Chance to same color for each color = \((\frac{20}{50}*\frac{19}{49})*2 + (\frac{5}{50}*\frac{4}{49})*2\) (times 2 because there are 20 Red and 20 blue, so same numbers and same thing for White and Green with 5 each.
\(= \frac{76}{245} + \frac{4}{245} = \frac{80}{245} = \frac{16}{49}\)
Chance to select one
arjtryarjtry
good one ... tis correct 
