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vivektripathi
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asdert
4C1 + 4C2 + 4C3 + 4C4 = 4 + 6 + 4 + 1 = 17
Good One !!!
I never get permutations and combinations and probabilty thanks for claryfying
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(4c1)+(4c2)+(4c3)+(4c4)= 4+6+4+1=15
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the calculations show 15 as the answer
what are the remaining 2 values for
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nikhiljain05
the calculations show 15 as the answer
what are the remaining 2 values for


I believe it was a mistake in addition. I did not notice it previously as I looked at the logic and I agreed with it.

If the subsets were not enumerated, we should have considered the null set, which is also a subset of any set.
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In Set Theory for every set {a1,a2... an} there are 2^n of subsets (power set).

In Set Theory {empty set} is also considerd a subset of {a1,a2.... an}

since you aren't being asked about {empty set} and n=4 then:

2^4-1 = 15

the answer is 15



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