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carsen
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There are 3 cases here: -

You can select: -

1. One French, One Spanish and One German in 4C1(French) X 6C2 (S + G) = 4 X 15 = 60

2. Two French and one Spanish or one German in 6C1 ( S / G) X 4C2 (F)

= 36
3. All the 3 french in 4C3 ways = 4

60+36+4 = 100

Alternately: -

You can select any 3 from the 10 in 10C3 ways ---------(1)

You can select persons other than French in 6C3 ways-------(2)

So the number of ways in which at least a french will be included in the committee is 10C3-6C3 = 120 - 20 = 100 ways
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Hi Mayur

Fantastic. I understood the 1st approach clearly. Thanks man.

Regards



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