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dhegdex
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dhegdex
on a certain site seeing tour, the ratio of the no: of women to the no: of children was 5:2. What was the no: of men on the site seeing tour??

stat 1> On the site seeing tour, the ratio of the no: of children to the no: of men was 5:11
stat 2> the no: of women on the site seeing tour was less than 30

I will go with C...

W:C
5:2

1) says C:M
5:11

so ratio now is

25:10:22

2) says no. of women is less than 30..

alone insuff..

together I know that no.of men is 22..
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fresinha12
dhegdex
on a certain site seeing tour, the ratio of the no: of women to the no: of children was 5:2. What was the no: of men on the site seeing tour??

stat 1> On the site seeing tour, the ratio of the no: of children to the no: of men was 5:11
stat 2> the no: of women on the site seeing tour was less than 30

I will go with C...

W:C
5:2

1) says C:M
5:11

so ratio now is

25:10:22

2) says no. of women is less than 30..

alone insuff..

together I know that no.of men is 22..

yeah..i guess you are right unless we can count the woman with no legs. We need integers. such a tricky test!
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spiridon
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C

it is possible to find out the m/w ratio using m and w against children rations so 22/25

since there was less then 30 females the number has to be in increments so 25
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KASSALMD
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Let women be = 5x
Men be = 11y
and
children be = 2x or 5y.(2x = 5y)
Therefore, 5x + 2x + 11y = T (total no. of people)
Substituting y for x we get,
25y/2 + 5y + 11y = T
57y/2 = T
Now from 2) women 60/25
Therefore y = 2
Therefore T = 57 and the respective nos. of women, men and children can be determined.
Ans is C.



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