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vksunder
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selvae
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scthakur
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vksunder
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OA - B.

scthakur - could you please explain statement b in detail. Thanks!
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gurpreet07
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Hi scthakur can u please explain your answer in more detail.
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scthakur
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From stmt2:
x^2 < 1, this means, -1 < x < 1
We need to compare (x-6), hence, subtract 6 from all the sides of the above inequality.
Thus, (-1-6) < (x-6) < (1-6)
or, -7 < (x-6) < -5

That means, absolute value of (x-6) will be between 5 and 7
i.e. 5 < |x-6| < 7

And this clearly explains that |x-6| > 5. Hence, sufficient.
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gurpreet07
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scthakur
From stmt2:
x^2 < 1, this means, -1 < x < 1
We need to compare (x-6), hence, subtract 6 from all the sides of the above inequality.
Thus, (-1-6) < (x-6) < (1-6)
or, -7 < (x-6) < -5

That means, absolute value of (x-6) will be between 5 and 7
i.e. 5 < |x-6| < 7

And this clearly explains that |x-6| > 5. Hence, sufficient.

so silly of me why couldn't i get this........
anyways thanks a lot
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GMAT TIGER
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vksunder
Is |x-6| > 5?

1. x is an integer
2. x^2 < 1

(x^2<1) and (x<1), which is not provided in the question, are two entirely different things but both are/would be sufficient to answer the question if x<1 were also provided as supplimentary information.

(x^2<1) has limits but (x<1) has no limit.
In (x^2<1), x is > -1 but < 1.
In (x<1), x could have any value smaller than 1.
So B is suff.
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I agree, it is B

I'd strongly recommend reading this https://www.manhattangmat.com/strategy-s ... -value.cfm for people having trouble with absolute value. It really helped me.
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[quote="vksunder"]Is |x-6| > 5?


1. x is an integer
2. x^2 5

If we consider x-6 to be +ve we get x > 11. If we consider x -ve we get x <1

so the Q is 11<x<1 ??

Clearly B says that x is +ve or -ve fraction or 0, all of those do not lie between 11 and 1

Hence B is suff



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