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Bunuel
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If n is an integer greater than 5.3, then n! must be divisible by whic 01 May 2019, 00:54
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C
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88% (00:52) correct 12% (01:08) wrong based on 191 sessions

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If n is an integer greater than 5.3, then n! must be divisible by which of the following numbers?

A. 7
B. 11
C. 12
D. 13
E. 14
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C
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If n is an integer greater than 5.3, then n! must be divisible by whic 01 May 2019, 01:01
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Hi Bunuel,



any integer greater than 5.3

can by any integer greater than or equal to 6

so we do not have any upper limit set here


Could you check once and correct me

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If n is an integer greater than 5.3, then n! must be divisible by whic 01 May 2019, 01:04
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The least value of n could be 6. So if take the factorial of 6, it should be divisible by all product of digits till 6.
So it should be divisible by 3*4= 12
IMO C

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If n is an integer greater than 5.3, then n! must be divisible by whic 01 May 2019, 01:04
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m1033512
Hi Bunuel,



any integer greater than 5.3

can by any integer greater than or equal to 6

so we do not have any upper limit set here


Could you check once and correct me

Posted from my mobile device
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You are correct m1033512
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If n is an integer greater than 5.3, then n! must be divisible by whic 01 May 2019, 01:05
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m1033512
Hi Bunuel,



any integer greater than 5.3

can by any integer greater than or equal to 6

so we do not have any upper limit set here


Could you check once and correct me

Posted from my mobile device
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If n is an integer greater than 5.3, then n! must be divisible by which of the following numbers?
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If n is an integer greater than 5.3, then n! must be divisible by whic 01 May 2019, 01:06
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Any integer greater than 5.3 will include 6 or above integers.

So min is 6!, and 6! is divisible by 6 as well as 2. (6x5x4x3x2x1)

Any number more than 6! will also be divisible by 6 and 2 (as 10! is also 10x9x8x7x6!). Hence it must be divisible by 12.

So in my opinion ans is (C)12.

So every integer factorial greater than 5.3 has to be divisible by 12.

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If n is an integer greater than 5.3, then n! must be divisible by whic 01 May 2019, 01:12
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m1033512
Hi Bunuel,



any integer greater than 5.3

can by any integer greater than or equal to 6

so we do not have any upper limit set here


Could you check once and correct me

Posted from my mobile device
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Each number starting from 6! has to divided by which number. Although no upper limit, there is lower limit.
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If n is an integer greater than 5.3, then n! must be divisible by whic 01 May 2019, 01:14
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Bunuel
If n is an integer greater than 5.3, then n! must be divisible by which of the following numbers?

A. 7
B. 11
C. 12
D. 13
E. 14
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Note : n is an integer.

Minimum value of n = 6.

6! = 6*5*4*3*2*1.

6! must be divisible by 6*2 = 12.

No upper limit is required here.

6! becomes the core of the system. Thus regardless of the the values of n, n! must be divisible by 6*2 =12.

Any other n! will have 6*2 as factors.

C is correct answer.
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If n is an integer greater than 5.3, then n! must be divisible by whic 23 Jun 2020, 08:09
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Given the fact that the number is bigger than 5 , n! Is at least 2*3*4*5
Only 12 satisfies this

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If n is an integer greater than 5.3, then n! must be divisible by whic 27 Jun 2020, 17:12
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Bunuel
If n is an integer greater than 5.3, then n! must be divisible by which of the following numbers?

A. 7
B. 11
C. 12
D. 13
E. 14
Show more

n is an integer greater than 5.3. n has to be 6.

6!=6*5*4*3*2*1

As we can see we have a 6 and 2 to make sure that 6! is divisible by 12.

Answer (C)
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If n is an integer greater than 5.3, then n! must be divisible by whic 31 Jan 2026, 09:22
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