Bunuel
Each of 30 members on a company's board voted once for one of four different contracts A,B,C or D. If there were no ties, and if each contract received at least 2 votes, and the contract receiving the most votes was selected, was contract A selected?
(1) Contract A received one vote less than contracts B and D together, and Contract C received 3 votes
(2) Contract A received 13 votes
A would win if it received the most contracts:
(1) Contract A received one vote less than contracts B and D together, and Contract C received 3 votes \(A+B+D = 27\)
\(A= B+D-1 \)
Therefore \(B+D-1+B+D =27\)
\(2(B+D)= 28\)
\(B+D = 14\)
Also \(C=3 \) ( Given )
Therefore A\(=30-17=13\)
If A receives \(13\) votes then no one else can receive more votes. Hence A was selected.
SUFF.
(2) Contract A received \(13\) votesLets assume someone else , got more votes than A
Then we have \(13 +14= 27 \) votes already
\(3\) more votes cannot be distributed between two people, such that each get atleast \(2\) votes.
Thus no one else got more than 13 votes. A wins.
SUFF.Ans D
Hope it's clear.