Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
(A): (1) SUFFICIENT: Manipulate the absolute value expression to represent this inequality on a number line: | 2x − 12 | < 10 | 2( x − 6) | < 10 2 | x − 6 | < 10 | x − 6 | < 5 This can be interpreted as “The distance between x and 6 is less than 5.” On a number line, this is the region between 1 and 11: All possible values for x are positive, so the answer to the question is a definite “Yes.” (2) INSUFFICIENT: Manipulate the inequality to get 0 on one side, thenfactor the resulting quadratic: x2 − 10x ≥ − 21 x2 − 10x + 21 ≥ 0 (x − 7)( x − 3) ≥ 0 The factored quadratic on the left side will equal 0 when x = 3 and 7. These are the boundary points. On a number line, check the regions on either side of these boundary points to determine the valid region( s) for x: Note that when 3 < x < 7, (x − 7)( x − 3) = (neg)( pos) = neg. Since both positive and negative values are possible for x, the answer is “Maybe.” The correct answer is (A).
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
(A): (1) SUFFICIENT: Manipulate the absolute value expression to represent this inequality on a number line: | 2x − 12 | < 10 | 2( x − 6) | < 10 2 | x − 6 | < 10 | x − 6 | < 5 This can be interpreted as “The distance between x and 6 is less than 5.” On a number line, this is the region between 1 and 11: All possible values for x are positive, so the answer to the question is a definite “Yes.” (2) INSUFFICIENT: Manipulate the inequality to get 0 on one side, thenfactor the resulting quadratic: x2 − 10x ≥ − 21 x2 − 10x + 21 ≥ 0 (x − 7)( x − 3) ≥ 0 The factored quadratic on the left side will equal 0 when x = 3 and 7. These are the boundary points. On a number line, check the regions on either side of these boundary points to determine the valid region( s) for x: Note that when 3 < x < 7, (x − 7)( x − 3) = (neg)( pos) = neg. Since both positive and negative values are possible for x, the answer is “Maybe.” The correct answer is (A).
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.