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kevincan
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GRE 1: Q170 V170
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GRE 1: Q170 V170
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amansingla4
D...


Could you please explain how it is D
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I`ll guess (B) too. Statement 1 is too broad and can result is several positive divisors like 6, 10, 26, etc...

Statement narrows the range to a set of non-divisible integers, both even and odd.
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B...but plz explain how it can be B
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jeunesis
B...but plz explain how it can be B


Lets see.
1. is not suff, because depending of the value of x the number of non-int quotients will be different. If x is 10 then 10/5 is not a non-int quotient, but if x is lets say 34 then 5/34 or 34/5 are both non-int quotients. So again, it depends on the value of x.
2. is suff, since it doesnt matter if x is even or odd, the number of non-int quotients will be same.

Hope this helps.
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jeunesis
B...but plz explain how it can be B

Lets see.
1. is not suff, because depending of the value of x the number of non-int quotients will be different. If x is 10 then 10/5 is not a non-int quotient, but if x is lets say 34 then 5/34 or 34/5 are both non-int quotients. So again, it depends on the value of x.
2. is suff, since it doesnt matter if x is even or odd, the number of non-int quotients will be same.

Hope this helps.


Good explanation. Chosing the second element 5, we can easily see that the number of non-integer results would be dependent on the fact whether x is a multiple of 5 or not. So the number of such results can vary. Hence invalid.

For (II) x belongs to {31,32,33,34}. Since all of these numbers are greater than all other numbers in W, the number of non-integer results can be precisely determined. So B.



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