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ashkrs
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GMAT 1: 680 Q48 V35
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GMATPrep - DS 24 Dec 2007, 22:52
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I cant comprehend this question. Makes me feel like a moron!
Can somebody rephrase this question ?



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LM
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GMATPrep - DS 24 Dec 2007, 23:37
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ashkrs
I cant comprehend this question. Makes me feel like a moron!
Can somebody rephrase this question ?
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a & n are = { 2,3,4,5,6,7,8....}

Product of first 8 positive integers is:

(2^7)*(3^2)*(5)*(7)


from (i) a^n = 64

2^6 = 64

4^3 = 64

from (ii)

n=6

we can have it possible only in case a^n = 2^6 which can divide the product of first 8 positive integers.

Therefore answer should be "B"
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GMATBLACKBELT
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GMATPrep - DS 26 Dec 2007, 00:36
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ashkrs
I cant comprehend this question. Makes me feel like a moron!
Can somebody rephrase this question ?
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should be B,

b/c we know a is greater than 1 so it must be +
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GMATPrep - DS 26 Dec 2007, 20:27
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i dont get this.

product of the first 8 positive integers is 8! isnt it ?
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gmatnub
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GMATPrep - DS 26 Dec 2007, 22:06
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wow, I thought that the gmat does not test intelligence, I stand corrected.

I would not have known where to begin.

LM, you are the man/woman.


Let me try to rephrase LM's work for my own practice and reference.

a and n are positive integers having possible values greater 1.

So a could be any number from 2,3,4,5,6,7,8,9....

So n could also be 2,3,4,5,6,7,8,9....

The phrase "the product of the first 8 positive integers" seems vague. How can you have 8 individual integers when a and n are just two integers? It would be more understandable if they add the word "possible" to the phrase to make it reads "the product of the first 8 'possible' positive integers". (but really, who would write a question like that an expect a real world answer?)

So the product of the first 8 possible integers:

2x3x4x5x6x7x8x9 = 2x3x2x2x5x2x3x7x2x2x2x3x3 = (2^7)*(3^4)*(5)*(7)


from (i) a^n = 64

possibilities are

2^6 = 64

4^3 = 64

8^2 = 64

a could be 2, 4, or 8 ---> Insuff

from (ii)

n=6 ---> SUFF

a can only be 2 because no other number can have the exponent that goes to 6 (although without doing math, i would NOT know for sure that 3^6 is no divisible by (2^7)*(3^4)*(5)*(7) )



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
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Thank you for understanding, and happy exploring!
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