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07 Nov 2009, 11:07
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07 Nov 2009, 12:24
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first translate the problem into simpler terms.
Let total number of students be x.
therefore, we are given:
no of students who dislike beans = (2/3)x
no of students who dislike beans and sprouts = (2/3)*(3/5)x = (2/5)x
[since we are given that 3/5 of the students who dont like beans also dont like sprouts this means that 2/5 of the students who dont like beans like sprouts]
therefore, no of students who dislike beans but like sprouts = (2/3)*(2/5)x = (4/15)x
thus if we know the total number of students we can answer the question.
(1) Sufficient: it gives us what we want directly.
(2) Sufficient: 40 students like beans. this accounts for (1/3) of the students. therefore if (1/3) is 40 then total is 120.
Thus choice D is the answer.
Let total number of students be x.
therefore, we are given:
no of students who dislike beans = (2/3)x
no of students who dislike beans and sprouts = (2/3)*(3/5)x = (2/5)x
[since we are given that 3/5 of the students who dont like beans also dont like sprouts this means that 2/5 of the students who dont like beans like sprouts]
therefore, no of students who dislike beans but like sprouts = (2/3)*(2/5)x = (4/15)x
thus if we know the total number of students we can answer the question.
(1) Sufficient: it gives us what we want directly.
(2) Sufficient: 40 students like beans. this accounts for (1/3) of the students. therefore if (1/3) is 40 then total is 120.
Thus choice D is the answer.
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10 Nov 2009, 08:28
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Nice explanation
+1 for you srihari
+1 for you srihari
