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05 Sep 2004, 16:09
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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1. vmt 0 IS v^2 x m^3 x t^-4 >0
1. m > v^2
2. m > t^-4
2. what is the value of (x-y)^4
1. product of x and y is 7
2. x and y are intergers
3. x people donated 500 each to a hospital. each of the x people persuaded x more people to donate 500. no one donated more than once and there were no other donations. what is value of x
1. the first x people doanted 1/16 of the toal amount
2. the total ammount donated was 120000
4. in the xy plane what is the slope of line l
1. line l does not cross line with eqn y = 1-x
2. line l cross line with eqn y = x-1
please explain your answers
1. m > v^2
2. m > t^-4
2. what is the value of (x-y)^4
1. product of x and y is 7
2. x and y are intergers
3. x people donated 500 each to a hospital. each of the x people persuaded x more people to donate 500. no one donated more than once and there were no other donations. what is value of x
1. the first x people doanted 1/16 of the toal amount
2. the total ammount donated was 120000
4. in the xy plane what is the slope of line l
1. line l does not cross line with eqn y = 1-x
2. line l cross line with eqn y = x-1
please explain your answers
Archived Topic
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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05 Sep 2004, 16:44
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Here goes....
(1) You'd better put this one down more clearly. I've long forgotten those logic signs, plus a comma here and there can totally change the given. Use words whenever you can, as that's what you'll find on the actual test!
(2) You need both the statements (A and B) to answer the question. If you only take statement A, the product can be of any two numbers, integers or not: e.g., 7 and 1, 3.5 and 2, 4 and 1.75, 5 and 1.4, etc. Statement B, however, limits your choices to either 7 and 1 or -7 and -1. Both of them will give you the same answer to your (x-y)^4, as the exponent is an even number.
(3) You can use either A or B to find the value of x.
The general equation is:
Total amount of donations = D = 500x +500(x)(x)
Using A, we have 500x/D = 1/16. It also means that 500(x)(x)/D = 15/16, which gives you an x value of 15.
Using B, you can simply solve the equation for x, which also gives you an x value of 15.
(4) You can answer the question by using statement A only. Since all you need to find is the slope of line l, which is parellel to the line y = 1-x, the slope of both the lines is the same (i.e., -1).
Also, since an infinite number of lines will cross the line y = x-1, statement B alone cannot be used to answer the question.
(1) You'd better put this one down more clearly. I've long forgotten those logic signs, plus a comma here and there can totally change the given. Use words whenever you can, as that's what you'll find on the actual test!
(2) You need both the statements (A and B) to answer the question. If you only take statement A, the product can be of any two numbers, integers or not: e.g., 7 and 1, 3.5 and 2, 4 and 1.75, 5 and 1.4, etc. Statement B, however, limits your choices to either 7 and 1 or -7 and -1. Both of them will give you the same answer to your (x-y)^4, as the exponent is an even number.
(3) You can use either A or B to find the value of x.
The general equation is:
Total amount of donations = D = 500x +500(x)(x)
Using A, we have 500x/D = 1/16. It also means that 500(x)(x)/D = 15/16, which gives you an x value of 15.
Using B, you can simply solve the equation for x, which also gives you an x value of 15.
(4) You can answer the question by using statement A only. Since all you need to find is the slope of line l, which is parellel to the line y = 1-x, the slope of both the lines is the same (i.e., -1).
Also, since an infinite number of lines will cross the line y = x-1, statement B alone cannot be used to answer the question.
05 Sep 2004, 17:08
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hi thanks for the answers. your answers are correct
on q1 here is another attempt at writing it. its hard becuase of all the eponents
v.m.t not equall to 0 (means v multipled by m and t is not equal to 0)
is v square times m cube times t to the -4 greater than 0
on q1 here is another attempt at writing it. its hard becuase of all the eponents
v.m.t not equall to 0 (means v multipled by m and t is not equal to 0)
is v square times m cube times t to the -4 greater than 0
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
