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Negation logic can be used as shown below

Required P = 1 - (P of atlease 1 blue) = 1 - (P of 1 blue AND 1 another color OR 2 blue)

= 1- [( (2C1 * 6C1) + 2C2 )/8C2) = 1 - 13/28 = 15/28

Hope it helps.



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