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16 Oct 2010, 13:29
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
69% (01:34) correct
31%
(01:47)
wrong
based on 144
sessions
History
Date
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A certain auto manufacturer sold 3% fewer vehicles in 2007 than in 2006. If the manufacturer sold 2.1 million vehicles in 2006, how many vehicles, to the nearest 10,000, did the manufacturer sell in 2007?
A. 63,000
B. 2,000,000
C. 2,030,000
D. 2,040,000
E. 2,300,000
A. 63,000
B. 2,000,000
C. 2,030,000
D. 2,040,000
E. 2,300,000
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16 Oct 2010, 16:25
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Let's assume in 2006 he has sold X. Therefore in 2007 he should have sold 97/100×X.
97/100×2100=2037
-->2,037,000 sold in 2007. When rounded to the nearest 10,000 :
2,040,000
97/100×2100=2037
-->2,037,000 sold in 2007. When rounded to the nearest 10,000 :
2,040,000
17 Oct 2010, 02:13
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Let's assume in 2006 the manufacturer sold X.
In 2007 he sold X-3/100(X)
If sales in 2006,X= 2.1 million find X-3/100(X)
(2.1 x 10^6)-3/100(2.1 x 10^6)
2100000-63000=2,037,000-----> 2,040,000(approx)
In 2007 he sold X-3/100(X)
If sales in 2006,X= 2.1 million find X-3/100(X)
(2.1 x 10^6)-3/100(2.1 x 10^6)
2100000-63000=2,037,000-----> 2,040,000(approx)
