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Option B.
Average of x,y and z=>(x+y+z)/3
x+y=8z(given)
Replacing we get,9z/3=3z
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Bunuel
The Official Guide For GMAT® Quantitative Review, 2ND Edition

If x + y= 8z, then which of the following represents the average (arithmetic mean) of x, y, and z, in terms of z ?

(A) 2z + 1
(B) 3z
(C) 5z
(D) z/3
(E) 3z/2

Problem Solving
Question: 104
Category: Arithmetic Percents
Page: 75
Difficulty: 550

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Average of x,y,z is (x+y+z)/3=(8z+z)/3=3z
:)
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Bunuel


If x + y= 8z, then which of the following represents the average (arithmetic mean) of x, y, and z, in terms of z ?

(A) 2z + 1
(B) 3z
(C) 5z
(D) z/3
(E) 3z/2


AM of x, y, z = (x+y+z)/3 = (8z+z)/3 = 3z

Correct Option: B
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x+y=8z then (x+y+)z/3=(8z+z)/3=9z/3=3z.
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Bunuel


If x + y= 8z, then which of the following represents the average (arithmetic mean) of x, y, and z, in terms of z ?

(A) 2z + 1
(B) 3z
(C) 5z
(D) z/3
(E) 3z/2

We need to determine the average of x, y, and z. In other words:

(x + y + z)/3 = ?

Since x + y = 8z, we can substitute 8z for x + y in our average formula and we have:

(8z + z)/3 = 9z/3 = 3z

Answer: B
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To find the average of x, y, and z in terms of z, we can use the formula for the average of three numbers.

The average is found by summing the numbers and then dividing the sum by the count of numbers. In this case, we have x, y, and z.

Given that x + y = 8z, we can rearrange the equation to solve for y:

y = 8z - x.

Now, let's calculate the average of x, y, and z:

Average = (x + y + z) / 3.

Substituting the value of y from the equation above, we have:

Average = (x + (8z - x) + z) / 3.

Simplifying this expression, we get:

Average = (8z + z) / 3.

Combining like terms, we have:

Average = 9z / 3.

Simplifying further, we get:

Average = 3z.

Therefore, the average of x, y, and z in terms of z is (B) 3z.
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Bunuel
If x + y = 8z, then which of the following represents the average (arithmetic mean) of x, y, and z, in terms of z ?

(A) 2z + 1
(B) 3z
(C) 5z
(D) z/3
(E) 3z/2





Nick Slavkovich, GMAT/GRE tutor with 20+ years of experience

[email protected]
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