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Paul
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Paul
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obada
Do we consider each man and woman a unique identity in such a question?

If this is not the case then the solution will be simply 19

How can a person not be unique :)
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venksune
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17C1*22C1 + 17C0*22C2 = whatever this may be.
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To find the no. of pairs consisting of atleast 1 women, find total possible no. of pairs i.e. (39C2) and subtract it from the total no of pairs that are both males. i.e. (17C2)

Hence the answer is 39C2 - 17C2 = 741 - 136 = 605

Regards

Subhen
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ruhi
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We can have a pair of two women or 1 man and 1 woman.
2 women can be selected in 22C2 ways=231
and 1 man and woman in 17C1*22C1 ways=374

total combination= 231+374=605.
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Paul
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OA is 605 :good



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