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11 Nov 2004, 08:54
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N
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
50% (00:00) correct
50%
(00:00)
wrong
based on 6
sessions
History
Date
Time
Result
Not Attempted Yet
How many 3- digit numbers between 100 and 200 have a digit that is the average of the other 2 digits?
A) 1
B) 7
C) 9
D) 11
E) 19
Does anyone know of a fast method to solve a problem like this?
Thanks.
A) 1
B) 7
C) 9
D) 11
E) 19
Does anyone know of a fast method to solve a problem like this?
Thanks.
Archived Topic
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11 Nov 2004, 11:58
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"C" it is.
the range is 101 - 199. so one digit out of three must be 1. the second can not be EVEN number bcoz any even + 1 = ODD and any ODD number can not have integer avg.
only possible - 1,3,5,7
by Considering
111,
132 and 123 - 231 / 321 are not possible....
thus, answer is 9
IMHO, such kind of questions demands Hands on experience.
please post OA
the range is 101 - 199. so one digit out of three must be 1. the second can not be EVEN number bcoz any even + 1 = ODD and any ODD number can not have integer avg.
only possible - 1,3,5,7
by Considering
111,
132 and 123 - 231 / 321 are not possible....
thus, answer is 9
IMHO, such kind of questions demands Hands on experience.
please post OA
