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15 Jun 2011, 22:41
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If the radius of the circle circumscribing a triangle is the same as one of the sides of an acute angled triangle, then what is the measure of the angle opposite the side?
A. 30
B. 45
C. 60
D. 90
E. 15
A. 30
B. 45
C. 60
D. 90
E. 15
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16 Jun 2011, 09:37
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vyassaptarashi
Could you please show how did you get the answer ?
Updated on: 17 Jun 2011, 07:37
Originally posted by vyassaptarashi on 17 Jun 2011, 02:46.
Last edited by vyassaptarashi on 17 Jun 2011, 07:37, edited 2 times in total.
Last edited by vyassaptarashi on 17 Jun 2011, 07:37, edited 2 times in total.
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I dont know how to get image here on the blog ... that would have been easy for u to understand ... but any ways .....
One side of the acute angle triangle is equal to radius. Therefore if we draw two straight lines on both ends of the side, which is = radius .. then it will form an equilateral triangle....since each of the two lines will be radius and the remaining is equal to radius.
Now we know that all angles in en equilateral triangle = 60 ....
hence the central angle will be equal to 60 degrees
Thus angle opposite to the side will be 1/2 central angle = 30
Hence A
In the diagram triangle ABC is an acute angle triangle and O is the center of the circle.
One side of the acute angle triangle is equal to radius. Therefore if we draw two straight lines on both ends of the side, which is = radius .. then it will form an equilateral triangle....since each of the two lines will be radius and the remaining is equal to radius.
Now we know that all angles in en equilateral triangle = 60 ....
hence the central angle will be equal to 60 degrees
Thus angle opposite to the side will be 1/2 central angle = 30
Hence A
In the diagram triangle ABC is an acute angle triangle and O is the center of the circle.
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