Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2301:30 AM EDT
-02:30 AM EDT
Struggling with GMAT Verbal as a non-native speaker? Harsh improved his score from 595 to 695 in just 45 days—and scored a 99 %ile in Verbal (V88)! Learn how smart strategy, clarity, and guided prep helped him gain 100 points.
Apr 2212:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2308:00 PM PDT
-09:00 PM PDT
Video explanations + diagnosis of 10 weakest areas + 150+ short videos + study plan!
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
06 Jul 2011, 12:44
Kudos
Bookmarks
N
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
0% (00:00) correct
100%
(01:06)
wrong
based on 4
sessions
History
Date
Time
Result
Not Attempted Yet
A photographer sets the 6 daughters of the Fuchs family in two equal rows. In each row,
the girls are ordered from the tallest on the left to the shortest on the right, and no girl on
the second row is shorter than the one in front of her. If no two girls are of equal height,
how many ways are there to set the Fuchs daughters for a photo?
(A) 4
(B) 5
(C) 6
(D) 24
(E) 36
the girls are ordered from the tallest on the left to the shortest on the right, and no girl on
the second row is shorter than the one in front of her. If no two girls are of equal height,
how many ways are there to set the Fuchs daughters for a photo?
(A) 4
(B) 5
(C) 6
(D) 24
(E) 36
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
06 Jul 2011, 13:17
Kudos
Bookmarks
firstly I would like to ask..."FUCHS", seriously? the book wrote that? lol 
solution has been discussed before https://gmatclub.com/forum/combinatory-problem-help-needed-70671.html...its a difficult problem
solution has been discussed before https://gmatclub.com/forum/combinatory-problem-help-needed-70671.html...its a difficult problem
07 Jul 2011, 03:13
Kudos
Bookmarks
I II III
1 2 3
Consider these to be the 6 places.
Consider the 6 heights to be H1, H2, H3, H4, H5 and H6 in increasing order.
It is obvious that H1 has to be at place 1 since H1 is shortest and H6 has to be at place III since H6 is tallest.
We only have to worry about H2, H3, H4 and H5.
Think about place 2 - People at places 3 and II have to be taller so H4 and H5 cannot come here. Only possibilities - H2/H3
Think about place 3 - Person there has to be taller than person at place 2. Only possibilities - H3/H4/H5
Think about place I - Person there has to be shorter than person at place II. Only possibilities - H2/H3/H4
Think about place II - Person there has to be taller than people at place I and 2. Only possibilities - H4/H5
Now just combine them in all possible ways:
H2, H3, H4, H5
H2, H4, H3, H5
H2, H5, H3, H4
H3, H4, H2, H5
H3, H5, H2, H4
5 ways
1 2 3
Consider these to be the 6 places.
Consider the 6 heights to be H1, H2, H3, H4, H5 and H6 in increasing order.
It is obvious that H1 has to be at place 1 since H1 is shortest and H6 has to be at place III since H6 is tallest.
We only have to worry about H2, H3, H4 and H5.
Think about place 2 - People at places 3 and II have to be taller so H4 and H5 cannot come here. Only possibilities - H2/H3
Think about place 3 - Person there has to be taller than person at place 2. Only possibilities - H3/H4/H5
Think about place I - Person there has to be shorter than person at place II. Only possibilities - H2/H3/H4
Think about place II - Person there has to be taller than people at place I and 2. Only possibilities - H4/H5
Now just combine them in all possible ways:
H2, H3, H4, H5
H2, H4, H3, H5
H2, H5, H3, H4
H3, H4, H2, H5
H3, H5, H2, H4
5 ways
