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cleetus
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jamifahad
Can this be done under two minutes? That's the question.

Lets see:

Let the 7 children have a,b,c,d,e,f,g cakes respectively.

First statement: The first child distributes his cake such that he is left with 4 cakes and rest have double their initial number of cakes:
hence:

a-(b+c+d+e+f+g) = 4 --- (i)

Second statement: the 2nd boy takes 2 cakes each from every one and is still 3 short of initial value of 1st.
Hence:

b+2 cakes(6 children) = a-3
or a-b = 15 --- (ii)

substituting this value in eq - 1.
a-b -(c+d+e+f+g) = 4

We get (c+d+e+f+g) = 11.
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I did this is 2:36. it is indeed a bit wordy but can certainly be done in ~2min. good question.
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Nice ques.. I took 3 mins bcoz I started in the wrong way initially.. :(
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@Sudhanshuacharya Wow! you made it look ridiculously easy.
+1.
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jamifahad
@Sudhanshuacharya Wow! you made it look ridiculously easy.
+1.

Thanks jamifahad. Glad you liked the solution



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