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karovd
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maaverick
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karovd
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twixt
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Log base 10 is a great idea to solve this one and maaverick reasoning is clear. I do not see any flaw anyway without using it and just looking at X structure I obtain K = 2.10^100

It is hard to believe that (10^100)^(10^100) = 10^(10^102)
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gayathri
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I got 10^102 as well.

x = 10^100

x^x = 10^k

x^x = (10^100)^(10^100) = 10^(100*10^100)

=> k = 100(10^100) = 10^102

It never occurred for me to use log! Thanks maaverick, its always good to know different ways to solve a problem. :-D
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revital
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can you explain how did you get it in more details , I dont get it :-(
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rthothad
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One more 10^102.

x = 10^100

x^x = 10^k => x = 10^k/x

So, 10^k/x = 10^100
=> k/x = 100

k = 100x = 100 * 10^100 = 10^102
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Paul
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Yet a slight variation, done in less than 1 min:
Try to get everything to base 10 since 10^k is what you are looking for
x^x = 10^(100 * 10^100)
= 10^(10^2 * 10^100)
= 10^(10^102) = 10^k
k = 10^102



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