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Posts: 23
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
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Question Stats:
28% (02:27) correct
72%
(02:23)
wrong
based on 2871
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Louie takes out a three-month loan of $1000. The lender charges him 10% interest per month compunded monthly. The terms of the loan state that Louie must repay the loan in three equal monthly payments. To the nearest dollar, how much does Louie have to pay each month?
A. 333
B. 383
C. 402
D. 433
E. 483
A. 333
B. 383
C. 402
D. 433
E. 483
sachinrelan
Let the monthly payment be \(x\).
After the 1st month there will be \(1,000*1.1-x\) dollars left to repay;
After the 2nd month there will be \((1,000*1.1-x)*1.1-x=1,210-2.1x\) dollars left to repay;
After the 3rd month there should be 0 dollars left to repay: \((1,210-2.1x)*1.1-x=0\):
\(1331=3.31x\);
\(x\approx{402}\).
\(x\approx{402}\).
Answer: C.
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sachinrelan
ok, there is an interest formula that i forget but lets do it another way:
so basically he is getting 10% interest per month for TWO month since he pays off in 3 months.
so 1000*1.1*1.1 = 1210
now divide by 3 = ~403.333
C
General Discussion
Posts: 135
\(CI = P(1+\frac{r}{100})^t\)
Assume he pays off entire amount in 3rd month or interest is accrued for 2 months. Find the amount at end of 3 months and divide by 3 to know monthly EMI
Assume he pays off entire amount in 3rd month or interest is accrued for 2 months. Find the amount at end of 3 months and divide by 3 to know monthly EMI
Posts: 23
shaselai
I Couldnt get why interest would be paid for 2 months, as per me
1. 1st month at the end monthly interest would be Accrued and monthly installment would be deducted from that amount.
2. For 2nd month start amount would be remaining amt of 1st month and at the end of 2nd month, monthly interest would be Accrued and thereafter again monthly installment would be deducted
3. For the 3rd month start amt would again be the remaning amt of 2nd month and at the end of 3rd month monthly interest would be accrued which should be equal to monthly installment.
So as per this interest was paid thrice ..request you to please clarify !!
sachinrelan
this is because you are paying off in the third and last months. This is assuming the interest rate is calculated at the end of the month. So it is assumed you paid off the balance at the end of third month so 0 balance. Like CC statements - if you didnt pay off your statement by end of month you get charged interest - you dont get charged interest throughout.
kostyan5
Joined: 29 Oct 2011
Last visit: 27 Apr 2021
Posts: 114
Concentration: General Management, Technology
Schools: Sloan '16 (D)
GMAT 1: 760 Q49 V44
GPA: 3.76
Actually what I wrote above assumes that Louie doesn't start repaying the loan immediately, instead he waits until all the interest has compounded. This is not necessarily correct since usually you start paying off loans as soon as you take them out. This means that you pay off some principle each month and therefore your interest is lower.
Here's the calculation for that case, assume monthly payment is X.
After 1st month: (1000)(1.1)-X = 1100-X
After 2nd month: (1100-X)(1.1)-X = 1210-2.21X
After 3rd month: (1210-2.21X)(1.1)-X = 1331-3.31X
Now, the amount after the last payment in 3rd month must bring the total to 0. Hence:
1331-3.31X = 0
X = 1331/3.31 = 402.11
The answer is C. However, I think this is a poorly worded question and on the real GMAT, they would specify that the payment is to be started immediately after loan inception.
Here's the calculation for that case, assume monthly payment is X.
After 1st month: (1000)(1.1)-X = 1100-X
After 2nd month: (1100-X)(1.1)-X = 1210-2.21X
After 3rd month: (1210-2.21X)(1.1)-X = 1331-3.31X
Now, the amount after the last payment in 3rd month must bring the total to 0. Hence:
1331-3.31X = 0
X = 1331/3.31 = 402.11
The answer is C. However, I think this is a poorly worded question and on the real GMAT, they would specify that the payment is to be started immediately after loan inception.
Posts: 27
The interest has to be calculated on a reducing balance.
If monthly repayment = x
At the end of the 3 month period,
1.1*[1.1*{1.1*(1000)-x}-x]-x = 0
=> 3.31x = 1331
=> x ~ 402
If monthly repayment = x
At the end of the 3 month period,
1.1*[1.1*{1.1*(1000)-x}-x]-x = 0
=> 3.31x = 1331
=> x ~ 402
Why are we assuming he pays from the 3rd month? The question does not specify that, it just says he has to pay in 3 installments.
Why not this way?
Total Loan disbursed in 3 months = 1.1 * 1.1* 1.1* 1000 = 1331
Repaid in 3 months, hence per month = 1331/3 = 443
Why not this way?
Total Loan disbursed in 3 months = 1.1 * 1.1* 1.1* 1000 = 1331
Repaid in 3 months, hence per month = 1331/3 = 443
rajatr
Joined: 09 Oct 2012
Last visit: 12 Nov 2014
Posts: 19
Concentration: Strategy
Schools: Bocconi '15 (A)
Schools: Bocconi '15 (A)
Posts: 19
In case of CI ,Repayment in equal installments (X) can be given as: 
X =P*r/ [1-(100/100+r)^n]
where X :each installment
r: rate
n: number of installments
P: Principal amount borrowed by borrower.
So in this case it would be 1000*10/[1-(10/11)^3] = 133100/331 = 402
X =P*r/ [1-(100/100+r)^n]
where X :each installment
r: rate
n: number of installments
P: Principal amount borrowed by borrower.
So in this case it would be 1000*10/[1-(10/11)^3] = 133100/331 = 402
Posts: 9
Bunuel
I get a different answer by using the Compound Interest formula, i.e- P[1 +(r)/100n]^nt
Since this formula uses annualized figures, so:
r = 10% per month = 120% per year
n = 12 (as interest is compounded monthly)
t = 3 months = 3/12 years
Using the formula for compound interest, I get:
P + C.I = 1000(1.1)^3 = 1331
So, EMI = 1331/3 = 443.66 which is ~ $444
What's wrong with this approach?
Thanks,
Ishan
ishanbhat455
Since he pays after each month, then after the firs month (after the first payment) the interest is calculated on reduced balance.
Does this make sense?
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junkostem
Joined: 20 Jul 2013
Last visit: 05 Jul 2024
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Since the loan = 1000, and this amount were to be charged 10% interest per month, compounded monthly ...
1000/3 = 333
1 --- 333 * 1.1 = 366
2 --- 366 * 1.1 = 402
3 --- 402 * 1.1 = 442
Sum the 3 months: 366 + 402 + 442 = 1210 total owed
3 equal installments: 1210/3 = roughly 403
The closest answer (sans the slight rounding): Choice C.
1000/3 = 333
1 --- 333 * 1.1 = 366
2 --- 366 * 1.1 = 402
3 --- 402 * 1.1 = 442
Sum the 3 months: 366 + 402 + 442 = 1210 total owed
3 equal installments: 1210/3 = roughly 403
The closest answer (sans the slight rounding): Choice C.
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sachinrelan
\(Amount = 1000( 1 + 10/100)^3\)
Amount is 1331
Since repayment is to be made in 3 equal installments , EMI is 1331/3 = 433 , Answer must be (D)
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Montyyy95
The solution will be as given by Bunuel in the comment on first page.
Why not this? Interest is always calculated on the outstanding amount only. If I pay say $400 at the end of month 1 out of the $1100 (P + I) till then, my interest in the second month will be charged on $700 only.
This calculation assumes no payment till month 3 to get the amount of $1331. That is not correct.
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Why is 10% being charged only to 1/3 of the total amount?
junkostem
CT2B
10% is applied to all three parts, and thus to the entire 1000. The point is: to one third it's applied once, to another third twice, and to the third third three times.
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