Last visit was: 25 Apr 2026, 10:38 It is currently 25 Apr 2026, 10:38
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
User avatar
MBAhereIcome
User avatar
Current Student
Joined: 07 Aug 2011
Last visit: 25 Feb 2016
Posts: 149
Own Kudos:
2,128
Given Kudos: 48
Status:mba here i come!
Posts: 149
Kudos: 2,128
probability 08 Jan 2012, 07:52
Kudos
Add Kudos
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
N
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

History

Date
Time
Result
Not Attempted Yet
selects 1 but at least one satisfies demand? are you sure that the question is correct?

Posted from my mobile device



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
User avatar
d3thknell
User avatar
Joined: 02 Mar 2011
Last visit: 11 Nov 2020
Posts: 42
Own Kudos:
73
Given Kudos: 42
Posts: 42
Kudos: 73
probability 09 Jan 2012, 03:37
Kudos
Add Kudos
Bookmarks
Bookmark this Post
there are 4 colors and 3 sizes. so we have a total of 4! x 3! number of toys
for red color there are 3 toys(one of each size)
for large toy there are 4 toys(1 of each color)
so total number of toys which can satisfy atleast one of the childs criteria are 3+4-1
we are deducting 1 because we are basically counting "large red toy" two times.
so probability =(4+3-1)/(3! x 4!)
=1/24
User avatar
mohan514
User avatar
Joined: 06 Jun 2011
Last visit: 29 Jul 2014
Posts: 106
Own Kudos:
64
Given Kudos: 1
Status:exam is close ... dont know if i ll hit that number
Location: India
Concentration: International Business, Marketing
GMAT Date: 10-09-2012
GPA: 3.2
Posts: 106
Kudos: 64
probability Updated on: 11 Jan 2012, 08:20
Originally posted by mohan514 on 09 Jan 2012, 06:29.
Last edited by mohan514 on 11 Jan 2012, 08:20, edited 1 time in total.
Kudos
Add Kudos
Bookmarks
Bookmark this Post
d3thknell
there are 4 colors and 3 sizes. so we have a total of 4! x 3! number of toys
for red color there are 3 toys(one of each size)
for large toy there are 4 toys(1 of each color)
so total number of toys which can satisfy atleast one of the childs criteria are 3+4-1
we are deducting 1 because we are basically counting "large red toy" two times.
so probability =(4+3-1)/(3! x 4!)
=1/24
Show more
it should be 1/12
coz sizes and four choices that should give 12 options??


correct me if i m wrong
User avatar
hamm0
User avatar
Joined: 31 Oct 2011
Last visit: 31 Mar 2015
Posts: 474
Own Kudos:
295
Given Kudos: 57
Schools: Johnson '16 (M)
GMAT 1: 690 Q45 V40
WE:Asset Management (Mutual Funds and Brokerage)
Schools: Johnson '16 (M)
GMAT 1: 690 Q45 V40
Posts: 474
Kudos: 295
probability 09 Jan 2012, 06:38
Kudos
Add Kudos
Bookmarks
Bookmark this Post
So, any red toy is desirable, as is any large toy.
My take..

There are 4 possible large toys (1 of each color) and 3 possible red toys (1 of each size). Here's where we have to be careful: we've counted the large red toy in both groups, so the total # of desired outcomes is 7-1=6, out of 12 total possible toys, to give us an answer of:

6/12 = 1/2

The question is confusing, but the driving point is: what is the probability that at least one of the color and model will satisfy the boy?

Checking via the long method yields the following:

yellow small
yellow middle
yellow large
blue small
blue middle
blue large
green small
green middle
green large
red small
red middle
red large

So there are 12 possibilities.

Now if we list the ones that have AT LEAST ONE of the qualities "red" or "large", we have:


yellow large
blue large
green large
red small
red middle
red large

so that leaves 6 possible outcomes.

So the final answer is 6/12 = 1/2
User avatar
d3thknell
User avatar
Joined: 02 Mar 2011
Last visit: 11 Nov 2020
Posts: 42
Own Kudos:
73
Given Kudos: 42
Posts: 42
Kudos: 73
probability 09 Jan 2012, 23:39
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mohan514
d3thknell
there are 4 colors and 3 sizes. so we have a total of 4! x 3! number of toys
for red color there are 3 toys(one of each size)
for large toy there are 4 toys(1 of each color)
so total number of toys which can satisfy atleast one of the childs criteria are 3+4-1
we are deducting 1 because we are basically counting "large red toy" two times.
so probability =(4+3-1)/(3! x 4!)
=1/24
it should be 1/8
coz 2 sizes and four choices that should give 8 options??


correct me if i m wrong
Show more

three sizes- large,medium and small

Hamm0 is right, total no. of toys is 4 x 3. i was wrong to calculate it as 4! x 3!



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderator:
Bunuel
Math Expert
109828 posts