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In a drawer of shirts, 8 are blue, 6 are green, and 4 are magenta. If Mason draws 2 shirts at random, what is the probability that at least one of the shirts he draws will be blue?
a) 25/153
b) 28/153
c) 5/17
d) 4/9
e) 12/17
a) 25/153
b) 28/153
c) 5/17
d) 4/9
e) 12/17
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17 Jan 2005, 12:24
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At least one Blue in two draws would be
BB + B not blue + not blue B
8/18 * 7/17 + 8/18 * 10/17 + 10/18 * 8/17
= 25/153
I am not sure what i am doign wrong
BB + B not blue + not blue B
8/18 * 7/17 + 8/18 * 10/17 + 10/18 * 8/17
= 25/153
I am not sure what i am doign wrong
