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swath20
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Right times two for vertical and horizontal...got it thanks.
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hmmmm.....

tricky question. for a moment i thought its C. but flags can be different if order is different. hence there are 120 ways. D
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christoph
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horizontal: 5 (for the first stripe 5 colors are possible) * 4 (for the second stripe 4 c are possible) * 3 (for the third stripe 3 c are possible) = 60
vertikal: 5*4*3 = 60

=> 120 D) !
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can someone suggest an easy, tried-and-tested way to distinguish between permutation and combination problems?
I mistakenly did 5c2 * 2 for this problem, which got me nowhere...
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But before going to end today I wanted to peep into this contagious forum :-)

Heres how I do....

5 colors and you need to pick 3 ----> 5 C 3 ways = 10

After picking 3 colors arranging them is 3! ways = 6

But we need to consider horizontal and vertical also = 2

So 10*6*2 =120


Thanks
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HongHu
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lastochka
can someone suggest an easy, tried-and-tested way to distinguish between permutation and combination problems?
I mistakenly did 5c2 * 2 for this problem, which got me nowhere...


Just ask yourself if you change the orders of two items, does it count as two outcomes for the question.



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