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B
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Difficulty:
55%
(hard)
Question Stats:
73% (03:23) correct
27%
(04:00)
wrong
based on 11
sessions
History
Date
Time
Result
Not Attempted Yet
In the parallelogram as shown in the figure, it is given AB=8 and BO=6 find BC
See attached all values are in cms:
Please note that 45 degrees as mentioned in attached is not mentioned in the question as I took the image from solutions.
(a). 12cm
(b). 2 sqrt(14) cm
(c). 2 sqrt(7) cm
(d). 10 cm
(e). 2 sqrt(11) cm
Source: Some document I had from internet
See attached all values are in cms:
Please note that 45 degrees as mentioned in attached is not mentioned in the question as I took the image from solutions.
(a). 12cm
(b). 2 sqrt(14) cm
(c). 2 sqrt(7) cm
(d). 10 cm
(e). 2 sqrt(11) cm
Source: Some document I had from internet
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11 Aug 2013, 03:26
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targetgmatchotu
\(\angle AOD = 90\) degree. Thus, \(\angle OAD = 45\)degrees\(\to\) OD = AO(sides opposite equal angles are equal).
Also, \(AO^2 = 8^2-6^2 = 28\). Now, in triangle AOD, \(AD^2 = AO^2+OD^2 = 2*AO^2 \to AD = 2\sqrt{14}.\)
As it is mentioned that ABCD is a parallelogram, AD = BC =\(2\sqrt{14}\)
11 Aug 2013, 04:09
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mau5
Sorry for that the angle given in the diagram as 45 degrees was not given in the question stem.I think I took the image from the solution and apologies for that.
You may now proceed again
Rgds,
TGC !
