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MaddieGMAT
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mau5
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MaddieGMAT
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MaddieGMAT
Even i arrived at a different answer, that's why i posted this question. Can u please post the steps you followed to solve the problem.

Total no of even integers between 10 and 100 :\(\frac{100-10}{2}+1 = 46\)

The no of even integers which have 3 as a multiple : # of multiples of 6 : \(\frac{96-12}{6}+1 = 15\)

Thus, the # of even integers that are not a multiple of 3 = 46-15 = 31.

Please cite the source if possible.
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I agree that it should be 31.

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