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Bunuel
A certain cake recipe states that the cake should be baked in a pan 8 inches in diameter. If Jules wants to use the recipe to make a cake of the same depth but 12 inches in diameter, by what factor should he multiply the recipe ingredients?

(A) 2 1/2
(B) 2 1/4
(C) 1 1/2
(D) 1 4/9
(E) 1 1/3



Hi genxer123
even the round pan will give you an answer..
round pan means it is cylinderical and by increasing diameter we are increasing the VOLUME..

volume of cylinder is \(pi*r^2h\)....
here radius are \(\frac{12}{2}=6\) and \(\frac{8}{2}=4\)
ans = \(\frac{V_{12}}{V_8} = \frac{pi*6^2*h}{pi*4^2*h}=\frac{36}{16}=\frac{9}{4}=2\frac{1}{4}\)

B
I stand corrected. My arithmetic was off on the round pan. Nice catch - thanks!
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84pi/40 pi

my ans is 2.1 closest to B but why isnt it just the same??
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Bunuel
A certain cake recipe states that the cake should be baked in a pan 8 inches in diameter. If Jules wants to use the recipe to make a cake of the same depth but 12 inches in diameter, by what factor should he multiply the recipe ingredients?

(A) 2 1/2
(B) 2 1/4
(C) 1 1/2
(D) 1 4/9
(E) 1 1/3
nabiharaza
84pi/40 pi

my ans is 2.1 closest to B but why isnt it just the same??
nabiharaza , I think your arithmetic might be incorrect, but I can't tell because I don't have your steps. How did you get \(84\pi\) and \(40\pi\)?

Let's say you want to take the changed volume approach (you can just check changed area, see my post above).

Choose any height for the round pan. It does not change. Let h = 3

A circular pan with an 8-inch diameter has a radius of 4 inches. Its volume, that of a cylinder:

\(\pi r^2h = \pi(16)(3) = 48\pi\)

A circular pan with a 12-inch diameter has a radius of 6 inches. h = 3. Its volume is

\(\pi r^2h = \pi(36)(3) = 108\pi\)

Increase factor?
\(\frac{108\pi}{48\pi}=\frac{9}{4}\) (divide LHS by 12)

= \(2 \frac{1}{4}\)

I hope that helps. If not, please show your steps? :-)
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Volume of 1st Cake (8inch diameter) * X times = Volume of 2nd Cake (12inch diameter)

(Pi 4^2 h)*x= Pi 6^2h
16x=36
x=9/4
That is 2 1/4
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