Let's visualize the problem step by step.
Given Information:
There are 5 married couples (including Mr. & Mrs. Smith), making a total of 10 people.
People can shake hands with others, except:
Themselves
Their own spouse
The same person more than once.
Each person gives a different number when asked how many handshakes they made.
Step 1: Maximum and Minimum Handshakes
Since each person can shake hands with at most 8 others (excluding their spouse and themselves), the possible handshake counts range from 0 to 8.
Since Mr. Smith got all distinct answers, the 9 people (excluding him) must have given handshake counts from 0 to 8.
Step 2: Identifying the Handshake Pattern
The person who said 0 did not shake hands with anyone.
The person who said 8 must have shaken hands with everyone except their spouse.
The person with 0 handshakes must be the spouse of the person with 8 handshakes (since they couldn't shake hands with each other).
Step 3: Eliminating Handshake Pairs
Remove the (0,8) couple from consideration.
Now, the remaining numbers are 1 to 7.
The person with 1 handshake must have shaken hands only with the one remaining person with the highest number left (7).
The person with 7 handshakes must have shaken hands with everyone except their spouse and the person with 0 handshakes.
Remove the (1,7) couple.
Continuing this pattern, we match (2,6), (3,5), leaving Mrs. Smith with 4 handshakes.
Before Mrs Smith, all answers were distinct, leaving Mr and Mrs smith with same handshakes that is 4Answer:
Mrs. Smith shook 4 hands.
Correct option:
C. 4