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03 Jun 2005, 00:54
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Hello
Can anyone explains me this ETS exercises
thanks
The volume of a box with a square
base is 54 cubic centimeters. If the height of the box is twice the width of the base, what is the height, in centimeters?
(A) 2
(B) 3
(C) 4
(D) 6
(E) 9
Can anyone explains me this ETS exercises
thanks
The volume of a box with a square
base is 54 cubic centimeters. If the height of the box is twice the width of the base, what is the height, in centimeters?
(A) 2
(B) 3
(C) 4
(D) 6
(E) 9
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03 Jun 2005, 02:53
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Volume of the box = length of base * width of base * height of box
as the base is square length = width.
Thus volume = w^2 * h
As stated height is 2 times width: h = 2w
thus volume:
w^2 * 2w = 54
w^3 = 54/2 = 27
w=3
which makes height equal 6
as the base is square length = width.
Thus volume = w^2 * h
As stated height is 2 times width: h = 2w
thus volume:
w^2 * 2w = 54
w^3 = 54/2 = 27
w=3
which makes height equal 6
03 Jun 2005, 02:57
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volume of a box is height * length * width
height = 2width and width = length. so its width * width * 2width=54 => width is 3 and height is 6.
height = 2width and width = length. so its width * width * 2width=54 => width is 3 and height is 6.
