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03 Nov 2014, 03:04
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
82% (01:07) correct
18%
(02:33)
wrong
based on 11
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Not Attempted Yet
In a garden, there are yellow and green flowers which are straight and curved. If the probability of picking a green flower is 3/4 and picking a straight flower is 1/2, then what is the probability of picking a flower which is yellow and straight
A) 1/7
B) 1/8
C) 1/4
D) 3/4
E) 7/8
A) 1/7
B) 1/8
C) 1/4
D) 3/4
E) 7/8
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09 Nov 2014, 21:13
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Hi swa730,
Good question.
So we have a garden where all the flowers have two properties: color (green or yellow) and shape (straight or curved).
We're told that 3/4 of the garden is green, so, since all the flowers must be either green or yellow, we know that 1/4 are yellow. We're also told there is an equal probability of straight or curved, 1/2.
We want to find out the probability of something being yellow and straight, Pr( Yellow and Straight ).
So if we recall, the probability of two unique events occurring simultaneously is the product of the two probabilities, Pr( A and B ) = P(A) * P(B). So we multiply the two probabilities, Pr(yellow)* Pr(straight) = 1/4 * 1/2 = 1/8, or B.
Hope this helps!
Good question.
Quote:
So we have a garden where all the flowers have two properties: color (green or yellow) and shape (straight or curved).
We're told that 3/4 of the garden is green, so, since all the flowers must be either green or yellow, we know that 1/4 are yellow. We're also told there is an equal probability of straight or curved, 1/2.
We want to find out the probability of something being yellow and straight, Pr( Yellow and Straight ).
So if we recall, the probability of two unique events occurring simultaneously is the product of the two probabilities, Pr( A and B ) = P(A) * P(B). So we multiply the two probabilities, Pr(yellow)* Pr(straight) = 1/4 * 1/2 = 1/8, or B.
Hope this helps!
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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