excelingmat
New Age has three consultants G, M and B. The sum of the number of projects handled by G and B individually is equal to the number of projects in which M
is involved. All three consultants are involved together in 6 projects. G works with M in 14 projects. B has 2 projects with M but without G, and 3 projects with G but without
M. The total number of projects for New Age Consultants is one less than twice the number of projects in which more than one consultant is involved.What is the number of projects in which M alone is involved?
(a) 0
(b) 1
(c) 3
(d) 4
(e) 5
As I understand we do not really need all that number information
Let's assume
G, B and M - projects alone
BG, BM, GM - projects in pair
BGM - all three consultant involved.
Quote:
sum of the number of projects handled by G and B individually is equal to the number of projects in which M is involved
G+B = Mx = GBM + GM + BM +M
Total number of projects:
T = BGM + BG + BM + GM +
B + G + M = 2(BGM + BG + BM + GM) -1
Since we already knew that G + B = Mx = GBM + GM + BM +M
T= BGM + BG + BM + GM +
GBM + GM + BM + M + M = 2BGM + 2BG + 2BM +2GM -1
2BGM+BG +2BM + 2GM + 2M = 2BGM + 2BG + 2BM +2GM -1
2BGM +
BG +
2BM +
2GM + 2M =
2BGM +
2BG +
2BM +
2GM -1
2M = BG -1
2M = 3 - 1
M = 1