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07 Mar 2014, 04:51
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B
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Difficulty:
5%
(low)
Question Stats:
93% (01:04) correct
7%
(01:17)
wrong
based on 1085
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An artist wishes to paint a circular region on a square poster that is 2 feet on a side. If the area of the circular region is to be 1/2 the area of the poster, what must be the radius of the circular region in feet?
(A) \(\frac{1}{\pi}\)
(B) \(\sqrt{\frac{2}{\pi}}\)
(C) \(1\)
(D) \(\frac{1}{\sqrt{\pi}}\)
(E) \(\frac{\pi}{2}\)
(A) \(\frac{1}{\pi}\)
(B) \(\sqrt{\frac{2}{\pi}}\)
(C) \(1\)
(D) \(\frac{1}{\sqrt{\pi}}\)
(E) \(\frac{\pi}{2}\)
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07 Mar 2014, 04:51
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SOLUTION
An artist wishes to paint a circular region on a square poster that is 2 feet on a side. If the area of the circular region is to be 1/2 the area of the poster, what must be the radius of the circular region in feet?
(A) \(\frac{1}{\pi}\)
(B) \(\sqrt{\frac{2}{\pi}}\)
(C) 1
(D) \(\frac{1}{\sqrt{\pi}}\)
(E) \(\frac{\pi}{2}\)
The area of the square poster = side^2 = 2^2 = 4.
The area of the circle must be half of that: \(\pi{r^2}=2\) --> \(r=\sqrt{\frac{2}{\pi}}\).
Answer: B.
An artist wishes to paint a circular region on a square poster that is 2 feet on a side. If the area of the circular region is to be 1/2 the area of the poster, what must be the radius of the circular region in feet?
(A) \(\frac{1}{\pi}\)
(B) \(\sqrt{\frac{2}{\pi}}\)
(C) 1
(D) \(\frac{1}{\sqrt{\pi}}\)
(E) \(\frac{\pi}{2}\)
The area of the square poster = side^2 = 2^2 = 4.
The area of the circle must be half of that: \(\pi{r^2}=2\) --> \(r=\sqrt{\frac{2}{\pi}}\).
Answer: B.
07 Mar 2014, 05:22
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Area of the poster = 2*2 = 4
Let r be the radius of the circular region.
Per question, Pi(r)^2 = 4/2 = 2
r^2 = 2/pi
r = (2/pi)^1/2
Answer (B).
Let r be the radius of the circular region.
Per question, Pi(r)^2 = 4/2 = 2
r^2 = 2/pi
r = (2/pi)^1/2
Answer (B).
